1/2(12p+8)+4p=2(p+4p)+4

Solution for 1/2(12p+8)+4p=2(p+4p)+4 equation:

1/2(12p+8)+4p=2(p+4p)+4

We move all terms to the left:

1/2(12p+8)+4p-(2(p+4p)+4)=0


Domain of the equation: 2(12p+8)!=0

p∈R


We add all the numbers together, and all the variables

1/2(12p+8)+4p-(2(+5p)+4)=0

We add all the numbers together, and all the variables

4p+1/2(12p+8)-(2(+5p)+4)=0

We multiply all the terms by the denominator


4p*2(12p+8)-((2(+5p)+4))*2(12p+8)+1=0


We calculate terms in parentheses: -((2(+5p)+4))*2(12p+8), so:

(2(+5p)+4))*2(12p+8


Wy multiply elements

8p^2(1-((2(+5p)+4))*2(12p+8)+1=0