3x-2(x+19)=9x-3(9-x)

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Solution for 3x-2(x+19)=9x-3(9-x) equation: 



3x-2(x+19)=9x-3(9-x)

We move all terms to the left:

3x-2(x+19)-(9x-3(9-x))=0

We add all the numbers together, and all the variables

3x-2(x+19)-(9x-3(-1x+9))=0

We multiply parentheses

3x-2x-(9x-3(-1x+9))-38=0



We calculate terms in parentheses: -(9x-3(-1x+9)), so:

9x-3(-1x+9)

We multiply parentheses

9x+3x-27

We add all the numbers together, and all the variables

12x-27

Back to the equation:

-(12x-27)



We add all the numbers together, and all the variables

x-(12x-27)-38=0

We get rid of parentheses

x-12x+27-38=0

We add all the numbers together, and all the variables

-11x-11=0

We move all terms containing x to the left, all other terms to the right

-11x=11

x=11/-11

x=-1

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