1/2(12+4x)=2(x-7)

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Solution for 1/2(12+4x)=2(x-7) equation: 



1/2(12+4x)=2(x-7)

We move all terms to the left:

1/2(12+4x)-(2(x-7))=0



Domain of the equation: 2(12+4x)!=0

x∈R



We add all the numbers together, and all the variables

1/2(4x+12)-(2(x-7))=0

We multiply all the terms by the denominator


-((2(x-7)))*2(4x+12)+1=0



We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*2(4x+12), so:

(2(x-7)))*2(4x+12





We calculate terms in parentheses: -((2(x-7)))*

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