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3x-2(10-4x)=4(3x-5)-x
We move all terms to the left:
3x-2(10-4x)-(4(3x-5)-x)=0
We add all the numbers together, and all the variables
3x-2(-4x+10)-(4(3x-5)-x)=0
We multiply parentheses
3x+8x-(4(3x-5)-x)-20=0
We calculate terms in parentheses: -(4(3x-5)-x), so:We add all the numbers together, and all the variables
4(3x-5)-x
We add all the numbers together, and all the variables
-1x+4(3x-5)
We multiply parentheses
-1x+12x-20
We add all the numbers together, and all the variables
11x-20
Back to the equation:
-(11x-20)
11x-(11x-20)-20=0
We get rid of parentheses
11x-11x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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