1/2(12)16+1/2(12)b2=168

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Solution for 1/2(12)16+1/2(12)b2=168 equation: 



1/2(12)16+1/2(12)b2=168

We move all terms to the left:

1/2(12)16+1/2(12)b2-(168)=0



Domain of the equation: 212b2!=0

b^2!=0/212

b^2!=√0

b!=0

b∈R



determiningTheFunctionDomain
1/212b2-168+1/21216=0

We calculate fractions

There is no solution for this equation

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