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1/2(10x-1)-3(x-4)=-21/2
We move all terms to the left:
1/2(10x-1)-3(x-4)-(-21/2)=0
Domain of the equation: 2(10x-1)!=0We multiply parentheses
x∈R
1/2(10x-1)-3x+12-(-21/2)=0
We get rid of parentheses
1/2(10x-1)-3x+12+21/2=0
We calculate fractions
-3x+12=0
We move all terms containing x to the left, all other terms to the right
-3x=-12
x=-12/-3
x=+4
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