n+32=4(n+5)+3n

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Solution for n+32=4(n+5)+3n equation: 



n+32=4(n+5)+3n

We move all terms to the left:

n+32-(4(n+5)+3n)=0



We calculate terms in parentheses: -(4(n+5)+3n), so:

4(n+5)+3n

We add all the numbers together, and all the variables

3n+4(n+5)

We multiply parentheses

3n+4n+20

We add all the numbers together, and all the variables

7n+20

Back to the equation:

-(7n+20)



We get rid of parentheses

n-7n-20+32=0

We add all the numbers together, and all the variables

-6n+12=0

We move all terms containing n to the left, all other terms to the right

-6n=-12

n=-12/-6

n=+2

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