1/16(12z-18)=2z-3

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Solution for 1/16(12z-18)=2z-3 equation: 



1/16(12z-18)=2z-3

We move all terms to the left:

1/16(12z-18)-(2z-3)=0



Domain of the equation: 16(12z-18)!=0

z∈R



We get rid of parentheses

1/16(12z-18)-2z+3=0

We multiply all the terms by the denominator


-2z*16(12z-18)+3*16(12z-18)+1=0

Wy multiply elements

-32z^2(1+48z(1+1=0

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