3/4(x-8)=1/3(x+27)

Solution for 3/4(x-8)=1/3(x+27) equation:

3/4(x-8)=1/3(x+27)

We move all terms to the left:

3/4(x-8)-(1/3(x+27))=0


Domain of the equation: 4(x-8)!=0

x∈R



Domain of the equation: 3(x+27))!=0

x∈R


We calculate fractions


(9xx/(4(x-8)*3(x+27)))+(-4xx/(4(x-8)*3(x+27)))=0


We calculate terms in parentheses: +(9xx/(4(x-8)*3(x+27))), so:

9xx/(4(x-8)*3(x+27))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)



We calculate terms in parentheses: +(-4xx/(4(x-8)*3(x+27))), so:

-4xx/(4(x-8)*3(x+27))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)


We get rid of parentheses

9xx-4xx=0