1/10b-3=5

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Solution for 1/10b-3=5 equation: 



1/10b-3=5

We move all terms to the left:

1/10b-3-(5)=0



Domain of the equation: 10b!=0

b!=0/10

b!=0

b∈R



We add all the numbers together, and all the variables

1/10b-8=0

We multiply all the terms by the denominator


-8*10b+1=0

Wy multiply elements

-80b+1=0

We move all terms containing b to the left, all other terms to the right

-80b=-1

b=-1/-80

b=1/80

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