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(3w-3)w=7
We move all terms to the left:
(3w-3)w-(7)=0
We multiply parentheses
3w^2-3w-7=0
a = 3; b = -3; c = -7;
Δ = b2-4ac
Δ = -32-4·3·(-7)
Δ = 93
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{93}}{2*3}=\frac{3-\sqrt{93}}{6} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{93}}{2*3}=\frac{3+\sqrt{93}}{6} $
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