1/10)x+149)=-2(3-x)

Solution for 1/10)x+149)=-2(3-x) equation:

1/10)x+149)=-2(3-x)

We move all terms to the left:

1/10)x+149)-(-2(3-x))=0


Domain of the equation: 10)x+149)-(-2(3!=0

x∈R


We add all the numbers together, and all the variables

1/10)x+149)-(-2(-1x+3))=0

We add all the numbers together, and all the variables

-1x+1/10)x+149)-(-2(=0

We multiply all the terms by the denominator


-1x*10)x+149)-(-2(+1=0

Wy multiply elements

-10x^2+1=0

a = -10; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-10)·1
Δ = 40
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40}=\sqrt{4*10}=\sqrt{4}*\sqrt{10}=2\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{10}}{2*-10}=\frac{0-2\sqrt{10}}{-20}
=-\frac{2\sqrt{10}}{-20}
=-\frac{\sqrt{10}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{10}}{2*-10}=\frac{0+2\sqrt{10}}{-20}
=\frac{2\sqrt{10}}{-20}
=\frac{\sqrt{10}}{-10}
$