1/10(10x-40)=2/5(-15x+15)

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Solution for 1/10(10x-40)=2/5(-15x+15) equation: 



1/10(10x-40)=2/5(-15x+15)

We move all terms to the left:

1/10(10x-40)-(2/5(-15x+15))=0



Domain of the equation: 10(10x-40)!=0

x∈R





Domain of the equation: 5(-15x+15))!=0

x∈R



We calculate fractions


(5x(-)/(10(10x-40)*5(-15x+15)))+(-20x1/(10(10x-40)*5(-15x+15)))=0



We calculate terms in parentheses: +(5x(-)/(10(10x-40)*5(-15x+15))), so:

5x(-)/(10(10x-40)*5(-15x+15))

We add all the numbers together, and all the variables

5x0/(10(10x-40)*5(-15x+15))

We multiply all the terms by the denominator


5x0

We add all the numbers together, and all the variables

5x

Back to the equation:

+(5x)





We calculate terms in parentheses: +(-20x1/(10(10x-40)*5(-15x+15))), so:

-20x1/(10(10x-40)*5(-15x+15))

We multiply all the terms by the denominator


-20x1

We add all the numbers together, and all the variables

-20x

Back to the equation:

+(-20x)



We get rid of parentheses

5x-20x=0

We add all the numbers together, and all the variables

-15x=0

x=0/-15

x=0

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