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2y-3=5+3(y-1)
We move all terms to the left:
2y-3-(5+3(y-1))=0
We calculate terms in parentheses: -(5+3(y-1)), so:We get rid of parentheses
5+3(y-1)
determiningTheFunctionDomain 3(y-1)+5
We multiply parentheses
3y-3+5
We add all the numbers together, and all the variables
3y+2
Back to the equation:
-(3y+2)
2y-3y-2-3=0
We add all the numbers together, and all the variables
-1y-5=0
We move all terms containing y to the left, all other terms to the right
-y=5
y=5/-1
y=-5
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