1/(x-6)=8/(2x)

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Solution for 1/(x-6)=8/(2x) equation: 



1/(x-6)=8/(2x)

We move all terms to the left:

1/(x-6)-(8/(2x))=0



Domain of the equation: (x-6)!=0

We move all terms containing x to the left, all other terms to the right

x!=6

x∈R





Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/(x-6)-(+8/2x)=0

We get rid of parentheses

1/(x-6)-8/2x=0

We calculate fractions


2x/(2x^2-12x)+(-8x+48)/(2x^2-12x)=0

We multiply all the terms by the denominator


2x+(-8x+48)=0

We get rid of parentheses

2x-8x+48=0

We add all the numbers together, and all the variables

-6x+48=0

We move all terms containing x to the left, all other terms to the right

-6x=-48

x=-48/-6

x=+8

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