4x-38=(3x-2)/5

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Solution for 4x-38=(3x-2)/5 equation: 



4x-38=(3x-2)/5

We move all terms to the left:

4x-38-((3x-2)/5)=0

We multiply all the terms by the denominator


4x*5)-((3x-2)-38*5)=0

We add all the numbers together, and all the variables

4x*5)-((3x-2)=0

Wy multiply elements

20x^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{40}=0$

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