1/(x-2)+1/(x+4)=8/7

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Solution for 1/(x-2)+1/(x+4)=8/7 equation:


D( x )

x+4 = 0

x-2 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:-4) U (-4:2) U (2:+oo)

1/(x-2)+1/(x+4) = 8/7 // - 8/7

1/(x-2)+1/(x+4)-(8/7) = 0

1/(x-2)+1/(x+4)-8/7 = 0

(1*7*(x+4))/(7*(x-2)*(x+4))+(1*7*(x-2))/(7*(x-2)*(x+4))+(-8*(x-2)*(x+4))/(7*(x-2)*(x+4)) = 0

1*7*(x+4)+1*7*(x-2)-8*(x-2)*(x+4) = 0

14*x-8*x^2-16*x+14+64 = 0

78-8*x^2-2*x = 0

78-8*x^2-2*x = 0

2*(39-4*x^2-x) = 0

39-4*x^2-x = 0

DELTA = (-1)^2-(-4*4*39)

DELTA = 625

DELTA > 0

x = (625^(1/2)+1)/(-4*2) or x = (1-625^(1/2))/(-4*2)

x = -13/4 or x = 3

2*(x+13/4)*(x-3) = 0

(2*(x+13/4)*(x-3))/(7*(x-2)*(x+4)) = 0

(2*(x+13/4)*(x-3))/(7*(x-2)*(x+4)) = 0 // * 7*(x-2)*(x+4)

2*(x+13/4)*(x-3) = 0

( x+13/4 )

x+13/4 = 0 // - 13/4

x = -13/4

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -13/4, 3 }

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