(x/x-3)=(x+3/x-1)

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Solution for (x/x-3)=(x+3/x-1) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x/x-3 = x+3/x-1 // - x+3/x-1

x/x-x-(3/x)-3+1 = 0

x/x-x-3*x^-1-3+1 = 0

-1*x^1-3*x^-1-1*x^0 = 0

(-1*x^2-1*x^1-3*x^0)/(x^1) = 0 // * x^2

x^1*(-1*x^2-1*x^1-3*x^0) = 0

x^1

-x^2-x-3 = 0

-x^2-x-3 = 0

DELTA = (-1)^2-(-3*(-1)*4)

DELTA = -11

DELTA < 0

x in { } 

x belongs to the empty set

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