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1/(x+2)=5
We move all terms to the left:
1/(x+2)-(5)=0
Domain of the equation: (x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
-5*(x+2)+1=0
We multiply parentheses
-5x-10+1=0
We add all the numbers together, and all the variables
-5x-9=0
We move all terms containing x to the left, all other terms to the right
-5x=9
x=9/-5
x=-1+4/5
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