8(2x+3)-5=10+4(4x-1)

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Solution for 8(2x+3)-5=10+4(4x-1) equation: 



8(2x+3)-5=10+4(4x-1)

We move all terms to the left:

8(2x+3)-5-(10+4(4x-1))=0

We multiply parentheses

16x-(10+4(4x-1))+24-5=0



We calculate terms in parentheses: -(10+4(4x-1)), so:

10+4(4x-1)

determiningTheFunctionDomain
4(4x-1)+10

We multiply parentheses

16x-4+10

We add all the numbers together, and all the variables

16x+6

Back to the equation:

-(16x+6)



We add all the numbers together, and all the variables

16x-(16x+6)+19=0

We get rid of parentheses

16x-16x-6+19=0

We add all the numbers together, and all the variables

13!=0

There is no solution for this equation

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