1/(2sin(2x))

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Solution for 1/(2sin(2x)) equation:


D( x )

2*sin(2*x) = 0

2*sin(2*x) = 0

2*sin(2*x) = 0

sin(2*x) = 0

sin(2*x) = 0 <=> 2*x = pi*k_1 i k_1 należy do I

t_1 = pi*k_1

2*x-t_1 = 0

2*x-t_1 = 0 // + t_1

2*x = t_1 // : 2

x = t_1/2

x = pi*k_1/2 i k_1 należy do I

2*sin(2*x) = 0 <=> 2 = 0 or 2*sin(2*x) = 0 <=> sin(2*x) = 0

x in {( -oo : +oo ) / < pi*k_1/2 : pi*k_1/2 >} i k_1 -> {I}

1/(2*sin(2*x)) = 0

1/(2*sin(2*x)) = 0 // * 2*sin(2*x)

1 = 0

x belongs to the empty set

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