-3(2b+1)+(7b-2)=0

Solution for -3(2b+1)+(7b-2)=0 equation:

Simplifying
-3(2b + 1) + (7b + -2) = 0

Reorder the terms:
-3(1 + 2b) + (7b + -2) = 0
(1 * -3 + 2b * -3) + (7b + -2) = 0
(-3 + -6b) + (7b + -2) = 0

Reorder the terms:
-3 + -6b + (-2 + 7b) = 0

Remove parenthesis around (-2 + 7b)
-3 + -6b + -2 + 7b = 0

Reorder the terms:
-3 + -2 + -6b + 7b = 0

Combine like terms: -3 + -2 = -5
-5 + -6b + 7b = 0

Combine like terms: -6b + 7b = 1b
-5 + 1b = 0

Solving
-5 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 1b = 0 + 5
1b = 0 + 5

Combine like terms: 0 + 5 = 5
1b = 5

Divide each side by '1'.
b = 5

Simplifying
b = 5