1-3x+x-6=-3(x-5)-(1+x)

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Solution for 1-3x+x-6=-3(x-5)-(1+x) equation: 



1-3x+x-6=-3(x-5)-(1+x)

We move all terms to the left:

1-3x+x-6-(-3(x-5)-(1+x))=0

We add all the numbers together, and all the variables

-3x+x-(-3(x-5)-(x+1))+1-6=0

We add all the numbers together, and all the variables

-2x-(-3(x-5)-(x+1))-5=0



We calculate terms in parentheses: -(-3(x-5)-(x+1)), so:

-3(x-5)-(x+1)

We multiply parentheses

-3x-(x+1)+15

We get rid of parentheses

-3x-x-1+15

We add all the numbers together, and all the variables

-4x+14

Back to the equation:

-(-4x+14)



We get rid of parentheses

-2x+4x-14-5=0

We add all the numbers together, and all the variables

2x-19=0

We move all terms containing x to the left, all other terms to the right

2x=19

x=19/2

x=9+1/2

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