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5x^2-1125=0
a = 5; b = 0; c = -1125;
Δ = b2-4ac
Δ = 02-4·5·(-1125)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22500}=150$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*5}=\frac{-150}{10} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*5}=\frac{150}{10} =15 $
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