1-3(x-2)=x-7(x+1)

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Solution for 1-3(x-2)=x-7(x+1) equation: 



1-3(x-2)=x-7(x+1)

We move all terms to the left:

1-3(x-2)-(x-7(x+1))=0

We multiply parentheses

-3x-(x-7(x+1))+6+1=0



We calculate terms in parentheses: -(x-7(x+1)), so:

x-7(x+1)

We multiply parentheses

x-7x-7

We add all the numbers together, and all the variables

-6x-7

Back to the equation:

-(-6x-7)



We add all the numbers together, and all the variables

-3x-(-6x-7)+7=0

We get rid of parentheses

-3x+6x+7+7=0

We add all the numbers together, and all the variables

3x+14=0

We move all terms containing x to the left, all other terms to the right

3x=-14

x=-14/3

x=-4+2/3

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