2(4x-16)-(32+6x)=18

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Solution for 2(4x-16)-(32+6x)=18 equation: 



2(4x-16)-(32+6x)=18

We move all terms to the left:

2(4x-16)-(32+6x)-(18)=0

We add all the numbers together, and all the variables

2(4x-16)-(6x+32)-18=0

We multiply parentheses

8x-(6x+32)-32-18=0

We get rid of parentheses

8x-6x-32-32-18=0

We add all the numbers together, and all the variables

2x-82=0

We move all terms containing x to the left, all other terms to the right

2x=82

x=82/2

x=41

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