1-(8-q)=4q+2(3q-6)

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Solution for 1-(8-q)=4q+2(3q-6) equation: 



1-(8-q)=4q+2(3q-6)

We move all terms to the left:

1-(8-q)-(4q+2(3q-6))=0

We add all the numbers together, and all the variables

-(-1q+8)-(4q+2(3q-6))+1=0

We get rid of parentheses

1q-(4q+2(3q-6))-8+1=0



We calculate terms in parentheses: -(4q+2(3q-6)), so:

4q+2(3q-6)

We multiply parentheses

4q+6q-12

We add all the numbers together, and all the variables

10q-12

Back to the equation:

-(10q-12)



We add all the numbers together, and all the variables

q-(10q-12)-7=0

We get rid of parentheses

q-10q+12-7=0

We add all the numbers together, and all the variables

-9q+5=0

We move all terms containing q to the left, all other terms to the right

-9q=-5

q=-5/-9

q=5/9

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