-1-7(1+8x)=40-8x

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Solution for -1-7(1+8x)=40-8x equation: 



-1-7(1+8x)=40-8x

We move all terms to the left:

-1-7(1+8x)-(40-8x)=0

We add all the numbers together, and all the variables

-7(8x+1)-(-8x+40)-1=0

We multiply parentheses

-56x-(-8x+40)-7-1=0

We get rid of parentheses

-56x+8x-40-7-1=0

We add all the numbers together, and all the variables

-48x-48=0

We move all terms containing x to the left, all other terms to the right

-48x=48

x=48/-48

x=-1

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