1-(2z-3)+6=3(z-4)

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Solution for 1-(2z-3)+6=3(z-4) equation: 


Simplifying
1 + -1(2z + -3) + 6 = 3(z + -4)

Reorder the terms:
1 + -1(-3 + 2z) + 6 = 3(z + -4)
1 + (-3 * -1 + 2z * -1) + 6 = 3(z + -4)
1 + (3 + -2z) + 6 = 3(z + -4)

Reorder the terms:
1 + 3 + 6 + -2z = 3(z + -4)

Combine like terms: 1 + 3 = 4
4 + 6 + -2z = 3(z + -4)

Combine like terms: 4 + 6 = 10
10 + -2z = 3(z + -4)

Reorder the terms:
10 + -2z = 3(-4 + z)
10 + -2z = (-4 * 3 + z * 3)
10 + -2z = (-12 + 3z)

Solving
10 + -2z = -12 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
10 + -2z + -3z = -12 + 3z + -3z

Combine like terms: -2z + -3z = -5z
10 + -5z = -12 + 3z + -3z

Combine like terms: 3z + -3z = 0
10 + -5z = -12 + 0
10 + -5z = -12

Add '-10' to each side of the equation.
10 + -10 + -5z = -12 + -10

Combine like terms: 10 + -10 = 0
0 + -5z = -12 + -10
-5z = -12 + -10

Combine like terms: -12 + -10 = -22
-5z = -22

Divide each side by '-5'.
z = 4.4

Simplifying
z = 4.4

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