Sin*(3x+2)=cos*(4x-10)

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Solution for Sin*(3x+2)=cos*(4x-10) equation: 


Simplifying
Sin(3x + 2) = cos(4x + -10)

Reorder the terms:
inS(2 + 3x) = cos(4x + -10)
(2 * inS + 3x * inS) = cos(4x + -10)
(2inS + 3inxS) = cos(4x + -10)

Reorder the terms:
2inS + 3inxS = cos(-10 + 4x)
2inS + 3inxS = (-10 * cos + 4x * cos)
2inS + 3inxS = (-10cos + 4cosx)

Solving
2inS + 3inxS = -10cos + 4cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
10cos + -4cosx + 2inS + 3inxS = -10cos + 4cosx + 10cos + -4cosx

Reorder the terms:
10cos + -4cosx + 2inS + 3inxS = -10cos + 10cos + 4cosx + -4cosx

Combine like terms: -10cos + 10cos = 0
10cos + -4cosx + 2inS + 3inxS = 0 + 4cosx + -4cosx
10cos + -4cosx + 2inS + 3inxS = 4cosx + -4cosx

Combine like terms: 4cosx + -4cosx = 0
10cos + -4cosx + 2inS + 3inxS = 0

The solution to this equation could not be determined.

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