1-(2y+2)-y=2(8y-8)

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Solution for 1-(2y+2)-y=2(8y-8) equation: 



1-(2y+2)-y=2(8y-8)

We move all terms to the left:

1-(2y+2)-y-(2(8y-8))=0

We add all the numbers together, and all the variables

-1y-(2y+2)-(2(8y-8))+1=0

We get rid of parentheses

-1y-2y-(2(8y-8))-2+1=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We add all the numbers together, and all the variables

-3y-(16y-16)-1=0

We get rid of parentheses

-3y-16y+16-1=0

We add all the numbers together, and all the variables

-19y+15=0

We move all terms containing y to the left, all other terms to the right

-19y=-15

y=-15/-19

y=15/19

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