8(-6+2c)-3c=-9

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Solution for 8(-6+2c)-3c=-9 equation: 



8(-6+2c)-3c=-9

We move all terms to the left:

8(-6+2c)-3c-(-9)=0

We add all the numbers together, and all the variables

8(2c-6)-3c-(-9)=0

We add all the numbers together, and all the variables

-3c+8(2c-6)+9=0

We multiply parentheses

-3c+16c-48+9=0

We add all the numbers together, and all the variables

13c-39=0

We move all terms containing c to the left, all other terms to the right

13c=39

c=39/13

c=3

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