1,365=25(t+13)

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Solution for 1,365=25(t+13) equation: 



1.365=25(t+13)

We move all terms to the left:

1.365-(25(t+13))=0



We calculate terms in parentheses: -(25(t+13)), so:

25(t+13)

We multiply parentheses

25t+325

Back to the equation:

-(25t+325)



We get rid of parentheses

-25t-325+1.365=0

We add all the numbers together, and all the variables

-25t-323.635=0

We move all terms containing t to the left, all other terms to the right

-25t=323.635

t=323.635/-25

t=-12+14.455657492355/15.290519877676

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