(40x-20)+(36-2x)+(8+x)=180

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Solution for (40x-20)+(36-2x)+(8+x)=180 equation: 



(40x-20)+(36-2x)+(8+x)=180

We move all terms to the left:

(40x-20)+(36-2x)+(8+x)-(180)=0

We add all the numbers together, and all the variables

(40x-20)+(-2x+36)+(x+8)-180=0

We get rid of parentheses

40x-2x+x-20+36+8-180=0

We add all the numbers together, and all the variables

39x-156=0

We move all terms containing x to the left, all other terms to the right

39x=156

x=156/39

x=4

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