1+log(x+1)=log(x-1)

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Solution for 1+log(x+1)=log(x-1) equation:


Simplifying
1 + log(x + 1) = log(x + -1)

Reorder the terms:
1 + glo(1 + x) = log(x + -1)
1 + (1 * glo + x * glo) = log(x + -1)
1 + (1glo + glox) = log(x + -1)

Reorder the terms:
1 + 1glo + glox = glo(-1 + x)
1 + 1glo + glox = (-1 * glo + x * glo)
1 + 1glo + glox = (-1glo + glox)

Add '-1glox' to each side of the equation.
1 + 1glo + glox + -1glox = -1glo + glox + -1glox

Combine like terms: glox + -1glox = 0
1 + 1glo + 0 = -1glo + glox + -1glox
1 + 1glo = -1glo + glox + -1glox

Combine like terms: glox + -1glox = 0
1 + 1glo = -1glo + 0
1 + 1glo = -1glo

Solving
1 + 1glo = -1glo

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add 'glo' to each side of the equation.
1 + 1glo + glo = -1glo + glo

Combine like terms: 1glo + glo = 2glo
1 + 2glo = -1glo + glo

Combine like terms: -1glo + glo = 0
1 + 2glo = 0

Add '-1' to each side of the equation.
1 + -1 + 2glo = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2glo = 0 + -1
2glo = 0 + -1

Combine like terms: 0 + -1 = -1
2glo = -1

Divide each side by '2lo'.
g = -0.5l-1o-1

Simplifying
g = -0.5l-1o-1

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