1+ln(x-2)+ln(x+2)=0

Solution for 1+ln(x-2)+ln(x+2)=0 equation:

Simplifying
1 + ln(x + -2) + ln(x + 2) = 0

Reorder the terms:
1 + ln(-2 + x) + ln(x + 2) = 0
1 + (-2 * ln + x * ln) + ln(x + 2) = 0
1 + (-2ln + lnx) + ln(x + 2) = 0

Reorder the terms:
1 + -2ln + lnx + ln(2 + x) = 0
1 + -2ln + lnx + (2 * ln + x * ln) = 0
1 + -2ln + lnx + (2ln + lnx) = 0

Reorder the terms:
1 + -2ln + 2ln + lnx + lnx = 0

Combine like terms: -2ln + 2ln = 0
1 + 0 + lnx + lnx = 0
1 + lnx + lnx = 0

Combine like terms: lnx + lnx = 2lnx
1 + 2lnx = 0

Solving
1 + 2lnx = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + 2lnx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2lnx = 0 + -1
2lnx = 0 + -1

Combine like terms: 0 + -1 = -1
2lnx = -1

Divide each side by '2nx'.
l = -0.5n-1x-1

Simplifying
l = -0.5n-1x-1