1+8(x-5)=9-8(x-7)

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Solution for 1+8(x-5)=9-8(x-7) equation:



1+8(x-5)=9-8(x-7)
We move all terms to the left:
1+8(x-5)-(9-8(x-7))=0
We multiply parentheses
8x-(9-8(x-7))-40+1=0
We calculate terms in parentheses: -(9-8(x-7)), so:
9-8(x-7)
determiningTheFunctionDomain -8(x-7)+9
We multiply parentheses
-8x+56+9
We add all the numbers together, and all the variables
-8x+65
Back to the equation:
-(-8x+65)
We add all the numbers together, and all the variables
8x-(-8x+65)-39=0
We get rid of parentheses
8x+8x-65-39=0
We add all the numbers together, and all the variables
16x-104=0
We move all terms containing x to the left, all other terms to the right
16x=104
x=104/16
x=6+1/2

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