2/7(28x+5)=10

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Solution for 2/7(28x+5)=10 equation: 



2/7(28x+5)=10

We move all terms to the left:

2/7(28x+5)-(10)=0



Domain of the equation: 7(28x+5)!=0

x∈R



We multiply all the terms by the denominator


-10*7(28x+5)+2=0

Wy multiply elements

-70x(2+2=0

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