1+5(2x-4)=4x+3-(6x+3-4x)

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Solution for 1+5(2x-4)=4x+3-(6x+3-4x) equation: 



1+5(2x-4)=4x+3-(6x+3-4x)

We move all terms to the left:

1+5(2x-4)-(4x+3-(6x+3-4x))=0

We add all the numbers together, and all the variables

5(2x-4)-(4x+3-(2x+3))+1=0

We multiply parentheses

10x-(4x+3-(2x+3))-20+1=0



We calculate terms in parentheses: -(4x+3-(2x+3)), so:

4x+3-(2x+3)

determiningTheFunctionDomain
4x-(2x+3)+3

We get rid of parentheses

4x-2x-3+3

We add all the numbers together, and all the variables

2x

Back to the equation:

-(2x)



We add all the numbers together, and all the variables

8x-19=0

We move all terms containing x to the left, all other terms to the right

8x=19

x=19/8

x=2+3/8

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