4(2y+5)=7(6+y)

Solution for 4(2y+5)=7(6+y) equation:

4(2y+5)=7(6+y)

We move all terms to the left:

4(2y+5)-(7(6+y))=0

We add all the numbers together, and all the variables

4(2y+5)-(7(y+6))=0

We multiply parentheses

8y-(7(y+6))+20=0


We calculate terms in parentheses: -(7(y+6)), so:

7(y+6)

We multiply parentheses

7y+42

Back to the equation:

-(7y+42)


We get rid of parentheses

8y-7y-42+20=0

We add all the numbers together, and all the variables

y-22=0

We move all terms containing y to the left, all other terms to the right

y=22