1+3x+5=2(x+-1)+(x+-3)

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Solution for 1+3x+5=2(x+-1)+(x+-3) equation: 



1+3x+5=2(x+-1)+(x+-3)

We move all terms to the left:

1+3x+5-(2(x+-1)+(x+-3))=0

We add all the numbers together, and all the variables

3x-(2(x-1)+(x-3))+1+5=0

We add all the numbers together, and all the variables

3x-(2(x-1)+(x-3))+6=0



We calculate terms in parentheses: -(2(x-1)+(x-3)), so:

2(x-1)+(x-3)

We multiply parentheses

2x+(x-3)-2

We get rid of parentheses

2x+x-3-2

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

3x-3x+5+6=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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