5x2+22x+21=0

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Solution for 5x2+22x+21=0 equation:



5x^2+22x+21=0
a = 5; b = 22; c = +21;
Δ = b2-4ac
Δ = 222-4·5·21
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-8}{2*5}=\frac{-30}{10} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+8}{2*5}=\frac{-14}{10} =-1+2/5 $

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