1+3b+b+2=7(5b-7)-8(5-5b)

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Solution for 1+3b+b+2=7(5b-7)-8(5-5b) equation: 



1+3b+b+2=7(5b-7)-8(5-5b)

We move all terms to the left:

1+3b+b+2-(7(5b-7)-8(5-5b))=0

We add all the numbers together, and all the variables

3b+b-(7(5b-7)-8(-5b+5))+1+2=0

We add all the numbers together, and all the variables

4b-(7(5b-7)-8(-5b+5))+3=0



We calculate terms in parentheses: -(7(5b-7)-8(-5b+5)), so:

7(5b-7)-8(-5b+5)

We multiply parentheses

35b+40b-49-40

We add all the numbers together, and all the variables

75b-89

Back to the equation:

-(75b-89)



We get rid of parentheses

4b-75b+89+3=0

We add all the numbers together, and all the variables

-71b+92=0

We move all terms containing b to the left, all other terms to the right

-71b=-92

b=-92/-71

b=1+21/71

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