4(u-3)=6u+1-2(-2u-1)

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Solution for 4(u-3)=6u+1-2(-2u-1) equation: 



4(u-3)=6u+1-2(-2u-1)

We move all terms to the left:

4(u-3)-(6u+1-2(-2u-1))=0

We multiply parentheses

4u-(6u+1-2(-2u-1))-12=0



We calculate terms in parentheses: -(6u+1-2(-2u-1)), so:

6u+1-2(-2u-1)

determiningTheFunctionDomain
6u-2(-2u-1)+1

We multiply parentheses

6u+4u+2+1

We add all the numbers together, and all the variables

10u+3

Back to the equation:

-(10u+3)



We get rid of parentheses

4u-10u-3-12=0

We add all the numbers together, and all the variables

-6u-15=0

We move all terms containing u to the left, all other terms to the right

-6u=15

u=15/-6

u=-2+1/2

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