1+3/5b=7/5b

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Solution for 1+3/5b=7/5b equation: 



1+3/5b=7/5b

We move all terms to the left:

1+3/5b-(7/5b)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R





Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

3/5b-(+7/5b)+1=0

We get rid of parentheses

3/5b-7/5b+1=0

We multiply all the terms by the denominator


1*5b+3-7=0

We add all the numbers together, and all the variables

1*5b-4=0

Wy multiply elements

5b-4=0

We move all terms containing b to the left, all other terms to the right

5b=4

b=4/5

b=4/5

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