1+2(a+1)=3(2a-2)

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Solution for 1+2(a+1)=3(2a-2) equation: 



1+2(a+1)=3(2a-2)

We move all terms to the left:

1+2(a+1)-(3(2a-2))=0

We multiply parentheses

2a-(3(2a-2))+2+1=0



We calculate terms in parentheses: -(3(2a-2)), so:

3(2a-2)

We multiply parentheses

6a-6

Back to the equation:

-(6a-6)



We add all the numbers together, and all the variables

2a-(6a-6)+3=0

We get rid of parentheses

2a-6a+6+3=0

We add all the numbers together, and all the variables

-4a+9=0

We move all terms containing a to the left, all other terms to the right

-4a=-9

a=-9/-4

a=2+1/4

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