1+(-3-3r)=-4(r+2)

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Solution for 1+(-3-3r)=-4(r+2) equation: 



1+(-3-3r)=-4(r+2)

We move all terms to the left:

1+(-3-3r)-(-4(r+2))=0

We add all the numbers together, and all the variables

(-3r-3)-(-4(r+2))+1=0

We get rid of parentheses

-3r-(-4(r+2))-3+1=0



We calculate terms in parentheses: -(-4(r+2)), so:

-4(r+2)

We multiply parentheses

-4r-8

Back to the equation:

-(-4r-8)



We add all the numbers together, and all the variables

-3r-(-4r-8)-2=0

We get rid of parentheses

-3r+4r+8-2=0

We add all the numbers together, and all the variables

r+6=0

We move all terms containing r to the left, all other terms to the right

r=-6

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