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(X+25)(2X+20)=180
We move all terms to the left:
(X+25)(2X+20)-(180)=0
We multiply parentheses ..
(+2X^2+20X+50X+500)-180=0
We get rid of parentheses
2X^2+20X+50X+500-180=0
We add all the numbers together, and all the variables
2X^2+70X+320=0
a = 2; b = 70; c = +320;
Δ = b2-4ac
Δ = 702-4·2·320
Δ = 2340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2340}=\sqrt{36*65}=\sqrt{36}*\sqrt{65}=6\sqrt{65}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-6\sqrt{65}}{2*2}=\frac{-70-6\sqrt{65}}{4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+6\sqrt{65}}{2*2}=\frac{-70+6\sqrt{65}}{4} $
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