1(b-6)+1=2(b-10)-3

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Solution for 1(b-6)+1=2(b-10)-3 equation:


Simplifying
1(b + -6) + 1 = 2(b + -10) + -3

Reorder the terms:
1(-6 + b) + 1 = 2(b + -10) + -3
(-6 * 1 + b * 1) + 1 = 2(b + -10) + -3
(-6 + 1b) + 1 = 2(b + -10) + -3

Reorder the terms:
-6 + 1 + 1b = 2(b + -10) + -3

Combine like terms: -6 + 1 = -5
-5 + 1b = 2(b + -10) + -3

Reorder the terms:
-5 + 1b = 2(-10 + b) + -3
-5 + 1b = (-10 * 2 + b * 2) + -3
-5 + 1b = (-20 + 2b) + -3

Reorder the terms:
-5 + 1b = -20 + -3 + 2b

Combine like terms: -20 + -3 = -23
-5 + 1b = -23 + 2b

Solving
-5 + 1b = -23 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-5 + 1b + -2b = -23 + 2b + -2b

Combine like terms: 1b + -2b = -1b
-5 + -1b = -23 + 2b + -2b

Combine like terms: 2b + -2b = 0
-5 + -1b = -23 + 0
-5 + -1b = -23

Add '5' to each side of the equation.
-5 + 5 + -1b = -23 + 5

Combine like terms: -5 + 5 = 0
0 + -1b = -23 + 5
-1b = -23 + 5

Combine like terms: -23 + 5 = -18
-1b = -18

Divide each side by '-1'.
b = 18

Simplifying
b = 18

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