2(b-6)+1=2(b-10)-3

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Solution for 2(b-6)+1=2(b-10)-3 equation:


Simplifying
2(b + -6) + 1 = 2(b + -10) + -3

Reorder the terms:
2(-6 + b) + 1 = 2(b + -10) + -3
(-6 * 2 + b * 2) + 1 = 2(b + -10) + -3
(-12 + 2b) + 1 = 2(b + -10) + -3

Reorder the terms:
-12 + 1 + 2b = 2(b + -10) + -3

Combine like terms: -12 + 1 = -11
-11 + 2b = 2(b + -10) + -3

Reorder the terms:
-11 + 2b = 2(-10 + b) + -3
-11 + 2b = (-10 * 2 + b * 2) + -3
-11 + 2b = (-20 + 2b) + -3

Reorder the terms:
-11 + 2b = -20 + -3 + 2b

Combine like terms: -20 + -3 = -23
-11 + 2b = -23 + 2b

Add '-2b' to each side of the equation.
-11 + 2b + -2b = -23 + 2b + -2b

Combine like terms: 2b + -2b = 0
-11 + 0 = -23 + 2b + -2b
-11 = -23 + 2b + -2b

Combine like terms: 2b + -2b = 0
-11 = -23 + 0
-11 = -23

Solving
-11 = -23

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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